Answer:
Fill the blank with [tex]\frac{8}{3}[/tex]
Step-by-step explanation:
Given
[tex]9xy * (\frac{2}{3}x)^3 = (--/--)x^4y[/tex]
Required
Fill in the gaps
[tex]9xy * (\frac{2}{3}x)^3 = (--/--)x^4y[/tex]
Open Brackets
[tex]9xy * \frac{2^3}{3^3}x^3 = (--/--)x^4y[/tex]
[tex]9xy * \frac{8}{27}x^3 = (--/--)x^4y[/tex]
Multiply xy and x^3
[tex]9 * \frac{8}{27}x^4y = (--/--)x^4y[/tex]
[tex]\frac{9 * 8}{27}x^4y = (--/--)x^4y[/tex]
Divide fraction by 9/9
[tex]\frac{8}{3}x^4y = (--/--)x^4y[/tex]
By comparison, the blank will be filled with:
[tex]\frac{8}{3}[/tex]
Hence, the solution to the question is: [tex]9xy * (\frac{2}{3}x)^3 = \frac{8}{3}x^4y[/tex]
