The 600-N ball shown is suspended on a string AB and rests against the frictionless vertical wall. The string makes an angle of 30° with the wall. The line AB goes through the center of the ball, and the contact point with the wall is at the same vertical height as the center of the ball. The ball presses against the wall with a force of magnitude:

Newton's second law gives a relationship between force, mass and acceleration of bodies. In the case where the acceleration is zero, it is called the equilibrium condition.

∑ F = 0

A free-body diagram is a diagram of the forces without the details of the bodies. In the attached we have a free-body diagram of the system.

Let's use trigonometry to break down stress.

sin 30 = [tex]\frac{T_x}{T}[/tex]

cos 30 = [tex]\frac{T_y}{T}[/tex]

T_y = T cos 30

Tₓ = T sin 30

Let's write the equilibrium condition for the system.

y-axis.

T_y -W = 0

T cos 30 = W

[tex]T = \frac{W}{cos 30}[/tex]

x-axis.

R - Tₓ = 0

R = T sin 30

We substitute

[tex]R = \frac{W}{cos 30} \ sin 30 \\R = W \ tan 30[/tex]

Let's calculate.

R = 600 tan 30

R = 346.4 N

This force is directed from the wall towards the ball, by Newton's third law the force of the ball is of equal magnitude and opposite direction, that is, directed towards the wall.

In conclusion with the equilibrium condition we can find the result for the force of the ball against the wall is:

The force of the ball directed towards the wall is 346.4 N

Learn more about the equilibrium condition here: brainly.com/question/18117041