Question

A single fair die is tossed. Find the odds in favor of rolling a number greater than 5

What are the odds in favor of rolling a number greater than 5?

Please help

Answer 1

Answer:

$1 : 5\ or\ \frac{1}5$

Step-by-step explanation:

Given that:

A single fair die is tossed.

First of all, let us learn about a fair die.

A fair die is a 6 sided die numbered from 1, 2, 3, to 6 and each side has an equal probability of occurring OR we can say each side is equally likely to occur.

So, probability of rolling a number greater than 5 has only one possible outcome i.e. 6.

And total number of outcomes are 6.

So, probability of rolling a number greater than 5 = $\frac{1}{6}$

Probability of not rolling a number greater than 5 = $\frac{5}{6}$

Odds in favor of rolling a number greater than 5 = Probability of rolling a number greater than 5 : Probability of not rolling a number greater than 5

$\dfrac{1}{6} :\dfrac{5}{6} = \bold{1:5}\ or\ \bold{\dfrac{1}{5}}$

Answer 2

Using the probability concept, the odds of rolling a number greater than 5 is 1 :5

The odd of a particular experiment is defined thus :

Number of possible outcomes greater than 5 : number of possible below or equal to 5

Sample space = {1, 2, 3, 4, 5, 6}

Outcomes greater than 5 = {6} = 1

Outcomes below or equal to 5 = {1, 2, 3, 4, 5} = 5

The odds equals to 1 : 5

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