Question

For the following reaction in aqueous solution, identify all the species that will be spectator ions. 2KF + Mg(CH3​COO)2----------​ 2KCH3​COO + MgF2​ Choose one or more: a. F– b. K c. Mg2 d. KCH3COO e. Mg(CH3COO)2 f. CH3COO– g. KF h. MgF2

Answer 1

Answer:

b. K⁺.

f. CH3COO⁻.

Explanation:

Hello!

In this case, since the reaction:

$2KF(aq) + Mg(CH_3COO)_2(aq)\rightarrow 2KCH_3COO(aq) + MgF_2(s)$

Has a precipitation product which is magnesium fluoride, it is not ionized so the ionic equation is:

$2K^+(aq)+F^-(aq) + Mg^{2+}(aq)+2CH_3COO^-(aq)\rightarrow 2K^++2CH_3COO^-(aq)(aq) + MgF_2(s)$

Thus, since potassium and acetate ions are at both reactants and product sides, we infer they are the spectator ions; therefore the answer is b. K⁺ and f. CH3COO⁻.

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Answer 2

The spectator ions are CH3COO– and K^+.

We must remember that spectator ions are the ions that do not undergo any change from left to right in the reaction equation.

The molecular reaction equation is;

2KF(aq) + Mg(CH3​COO)2(aq)----------​ >2KCH3​COO(aq) + MgF2​ (s)

Complete ionic reaction equation is;

2K^+(aq) + 2F^-(aq) + Mg^2+(aq) + 2CH3​COO^-(aq) ----> 2K^+(aq) +  2CH3​COO^-(aq) + MgF2​ (s)

Eliminating the spectator ions, we have the net ionic reaction equation;

Mg^2+(aq) + 2F^-(aq) ------> MgF2​ (s)

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