Answer:
[tex]5\sqrt{5}i[/tex] or D
Step-by-step explanation:
[tex]\sqrt{-125} \\\\\mathrm{Apply\:radical\:rule}:\quad \sqrt{-a}=\sqrt{-1}\sqrt{a}\\\\\sqrt{-125}=\sqrt{-1}\sqrt{125}\\\\=\sqrt{-1}\sqrt{125}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\=\sqrt{125}i\\\\=5\sqrt{5}i[/tex]
