Answer:
1) 90 mi
2) 4 inch
Step-by-step explanation:
1)
Given that the distance between Fairview and Abbots Rise on the map = 5 in
Scale of the map = 1 in: 18 mi
i.e. 1 inch on map is equivalent to an actual distance equal to 18 mi between the cities.
Given that the map has a distance of 5 inches.
Therefore, the actual distance between the cities = 5 [tex]\times[/tex] 18 = 90 mi
2) A particular satellite is 12 ft wide.
Model's scale = 1 in : 3 ft
i.e. 1 inch on map is equivalent to actual distance of 3 ft.
OR
3 ft of actual distance = 1 in on map
1 ft of actual distance = [tex]\frac{1}{3}[/tex] in on map
12 ft of actual distance = [tex]\frac{1}{3}\times 12 = \bold{4\ inch}[/tex]
