Answer:
0
Explanation:
Given that:
The peak of the voltage [tex]V_{peak}[/tex] = 12 V
The frequency f = 50 Hz
At the time t = 10 ms
[tex]V = V_p \ sin \ \omega t[/tex]
where;
[tex]\omega = 2 \pi f[/tex]
[tex]V = 1 2\ V \times sin \ ( 2 \pi \times 50 \times 10 \ )[/tex]
V = 12V sin (180)
V = 12 V × 0
V = 0