Question

Christina drives her moped 7 kilometers North. She stops for lunch and then drives 5 kilometers East.

What distance did she cover? Please include the number and unit.

What was the magnitude of her displacement? Please include the number and unit.

What was the direction of her displacement? Please abbrieviate (N, S, E, W, etc.)

Answer 1

Explanation:

Given that,

Christina drives her moped 7 kilometers North. She stops for lunch and then drives 5 kilometers East. At first she traveled North and then East. They are perpendicular to each other.

Total path traveled = distance covered by an object

D = 7 km + 5 km = 12 km

Shortest path covered = Displacement

$d=\sqrt{7^2+5^2} \\\\d=8.6\ km$

For direction :

$\tan\theta=\dfrac{d_y}{d_x}\\\\\tan\theta=\dfrac{7}{5}\\\\\theta=\tan^{-1}(\dfrac{7}{5})\\\\\theta=54.46^{\circ}$

She is moving in the direction of 54.46 degrees.