Question

1.5.3

6x+7

To solve for the lengths of the right triangle sides, which equation is correct?

A. x² = (4x - 1)² + (6x + 7)?

B. x2 +(6x + 7)2 = (4x - 1)2

c. x² = (4x - 1)² – (6x + 772

D.x² + (4x - 1)2 = (6x + 7)?

4x-1

To solve for the lengths of the right triangle sides, equation is correct.

(Type A, B, C, or D.)

Answer 1

Answer:

A. $x^2 = (4x - 1)^2 + (6x + 7)^2$

Step-by-step explanation:

The question seems to be incomplete. However, we'll make the following assumption.

$Opposite = 6x + 7$

$Adjacent = 4x - 1$

$Hypothenuse = x$

Pythagoras theorem states that:

$Hypothenuse^2 = Opposite^2 + Adjacent^2$

Substitute values for Hypothenuse, Opposite and Adjacent.

This gives

$x^2 = (6x + 7)^2 + (4x - 1)^2$

or

$x^2 = (4x - 1)^2 + (6x + 7)^2$

From the list of given options.

A answers the question