Question

A cross- country skier moves from location A to location B to location C to location D. Each leg of the back and forth motion takes 1 minute to complete; the total time is 3 minutes . Wes =0 min t - 2min t = 3mim t = 1min 100 What is the distance travelled by the skier in the first 3 minutes? What is the net displacement of the skier in the first 3 minutes? - What is the displacement during the second minute? What is the displacement during the third minute?

Answer 1

Answer:

hello some parts of your question is missing attached below is the missing part

Answer :

a) 360 m

b) 120 m  ( eastward )

c) -120 m ( westward )

d) 80 m  ( eastward )

Explanation:

given data:

Each leg time = 1 minute

Total time = 3 minutes

t=0        t= 2            t = 3             t = 1

xo =0     x2 = 40     x3 = 120       x1 = 160

a) Distance travelled by skier in first 3 minutes

d = | x1 - xo | + | x2 - x1 | + | x3 - x2 |

    = 160 + 120 + 80 = 360 m

b) net displacement in first 3 minutes

s = ( x1 -x0 ) + ( x2 - x1 ) + ( x3 -x2 )

  = 120 m  ( eastward )

c) displacement during the second minute

s1 = x2 - x1  = 40 - 160  = -120 m ( westward )

d) displacement during the third minute

s2 = x3 - x2 = 120 - 40 = 80 m  ( eastward )

Answer 2

(a) The distance traveled by the skier in the first 3 minutes is 360.

(b) The displacement of the skier during the second minute is 120 west.

(c) The displacement of the skier during the third minute is 80 east.

The given parameters;

• distance traveled in 1 min = 160
• distance traveled in  2 min = 20
• distance traveled in 3 min = 120

The distance traveled by the skier in the first 3 minutes is calculated as follows;

$x = (120 - 40) + 120 + 160\\\\x = 360$

The displacement of the skier during the second minute is calculated as follows;

$x= (x_2 - x_1)\\\\x = 40 - 160\\\\x = -120 \ \\\\x = 120 \ west$

The displacement of the skier during the third minute is calculated as follows;

$x = (x_3 - x_2)\\\\x = 120 - 40\\\\x = 80 \ east$

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