contestada

A force of 70 N is inclined at an angle
of 30° to the horizontal. Calculate its
horizontal and vertical components
respectively.​

Respuesta :

Answer:

The horizontal component of the 70 N force = 35·√3 N

The vertical component of the 70 N force = 35 N

Explanation:

The magnitude of the given force, F = 70 N

The angle of inclination of the given force to the horizontal, θ = 30°

By the resolution of forces, we can resolve the given force, F, into its horizontal component, Fₓ, and vertical components, [tex]F_y[/tex], as follows;

The horizontal component of the given force = Fₓ = F × cos(θ)

Substituting the values, we have;

The horizontal component of the 70 N force, Fₓ = 70 × cos(30°) = 35·√3 N

The vertical component of the given force = [tex]F_y[/tex] = F × sin(θ)

Substituting the values, we have;

The vertical component of the 70 N force, [tex]F_y[/tex] = 70 × sin(30°) = 35 N.

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