Question

write a Pythagorean triplet whose smallest value is 14​

Answer 1

Here is one: (14, 48, 50)

Answer 2

Formula=(2m)²,(m²-1)².(m²+1)²

according to ques
smallest number =14
means 2m =14
m=14/2=7

m²-1= 7²-1= 49-1= 48

m²+1=7²+1= 49+1=50

hence the required triplet is 14, 48 and 50