Answer:
Equation of line in Point Slope Form is [tex]\mathbf{y-2=-2(x-9)}[/tex]
Equation of line in Slope Intercept Form is: [tex]\mathbf{y=-2x+20}[/tex]
Step-by-step explanation:
We need to write equation of line having slope -2 and point (9,2)
a) Equation in Point Slope Form
The general equation of point slope form is: [tex]y-y_1=m(x-x_1)[/tex]
Where x₁ and y₁ are the points of line and m is slope.
x₁=9 and y₁=2 and m=-2
Putting values in formula and finding equation:
[tex]y-y_1=m(x-x_1)\\y-2=-2(x-9)[/tex]
So, Equation of line in Point Slope Form is [tex]\mathbf{y-2=-2(x-9)}[/tex]
b) Equation in Slope Intercept Form
The general equation of Slope Intercept Form is: [tex]y=mx+b[/tex]
where m is slope and b is y-intercept
Finding y-intercept using slope m=-2 and point(9,2)
[tex]y=mx+b\\2=-2(9)+b\\2=-18+b\\b=2+18\\b=20[/tex]
The equation in slope m=-2 and b=20 is:
[tex]y=mx+b\\y=-2x+20[/tex]
So, equation of line in Slope Intercept Form is: [tex]\mathbf{y=-2x+20}[/tex]