Respuesta :

Answer:

Equation of line in Point Slope Form is [tex]\mathbf{y-2=-2(x-9)}[/tex]

Equation of line in Slope Intercept Form is: [tex]\mathbf{y=-2x+20}[/tex]

Step-by-step explanation:

We need to write equation of line having slope -2 and point (9,2)

a) Equation in Point Slope Form

The general equation of point slope form is: [tex]y-y_1=m(x-x_1)[/tex]

Where x₁ and y₁ are the points of line and m is slope.

x₁=9 and y₁=2 and m=-2

Putting values in formula and finding equation:

[tex]y-y_1=m(x-x_1)\\y-2=-2(x-9)[/tex]

So, Equation of line in Point Slope Form is [tex]\mathbf{y-2=-2(x-9)}[/tex]

b) Equation in Slope Intercept Form

The general equation of Slope Intercept Form is: [tex]y=mx+b[/tex]

where m is slope and b is y-intercept

Finding y-intercept using slope m=-2 and point(9,2)

[tex]y=mx+b\\2=-2(9)+b\\2=-18+b\\b=2+18\\b=20[/tex]

The equation in slope m=-2 and b=20 is:

[tex]y=mx+b\\y=-2x+20[/tex]

So, equation of line in Slope Intercept Form is: [tex]\mathbf{y=-2x+20}[/tex]

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