Respuesta :

Answer:

[tex]\log _b\left(\sqrt{\frac{57}{74}}\right)[/tex] is equivalent to  [tex]\frac{1}{2}\left(\log \:_b\left(57\right)-\log \:_b\left(74\right)\right)[/tex].

Hence, option 'c' is true.

Step-by-step explanation:

Given the expression

[tex]\log _b\left(\sqrt{\frac{57}{74}}\right)[/tex]

Rewrite as

[tex]=\log _b\left(\left(\frac{57}{74}\right)^{\frac{1}{2}}\right)[/tex]

[tex]\mathrm{Apply\:log\:rule\:}\log _a\left(x^b\right)=b\cdot \log _a\left(x\right),\:\quad \mathrm{\:assuming\:}x\:\ge \:0[/tex]

[tex]=\frac{1}{2}\log _b\left(\frac{57}{74}\right)[/tex]

[tex]\mathrm{Apply\:log\:rule}:\quad \log _c\left(\frac{a}{b}\right)=\log _c\left(a\right)-\log _c\left(b\right)[/tex]

[tex]=\frac{1}{2}\left(\log _b\left(57\right)-\log _b\left(74\right)\right)[/tex]     ∵ [tex]\log _b\left(\frac{57}{74}\right)=\log _b\left(57\right)-\log _b\left(74\right)[/tex]

Therefore,

[tex]\log _b\left(\sqrt{\frac{57}{74}}\right)[/tex] is equivalent to  [tex]\frac{1}{2}\left(\log \:_b\left(57\right)-\log \:_b\left(74\right)\right)[/tex].

Hence, option 'c' is true.

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