help please..........

Answer:
Step-by-step explanation:
[tex]tan (\frac{\theta}{2} )- sin \theta=0\\\frac{sin\frac{\theta}{2}}{cos\frac{\theta}{2}} -2 sin \frac{\theta}{2}cos \frac{\theta}{2}=0\\sin \frac{\theta}{2}(1-2 cos^2 \frac{\theta}{2})=0\\sin \frac{\theta}{2}=0=sin n\pi \\\theta=2n\pi ,where~n~is~an~integer.\\or\\2 cos^2\frac{\theta}{2}=1\\1+cos \theta=1\\cos~\theta=0=cos (2n+1)\frac{\pi }{2}\\\theta=(2n+1)\frac{\pi }{2},where~n~is~an~integer.[/tex]