Answer:
The required heat flux = 12682.268 W/m²
Explanation:
From the given information:
The initial = 25°C
The final = 75°C
The volume of the fluid = 0.2 m/s
The diameter of the steel tube = 12.7 mm = 0.0127 m
The fluid properties for density [tex]\rho[/tex] = 1000 kg/m³
The mass flow rate of the fluid can be calculated as:
[tex]m = pAV[/tex]
[tex]m = \rho \dfrac{\pi}{4}D^2V[/tex]
[tex]m = 1000 \times \dfrac{\pi}{4} \times ( 0.0127)^2 \times 0.2[/tex]
[tex]m = 0.0253 \ kg/s[/tex]
To estimate the amount of the heat by using the expression:
[tex]q = mc_p(T_{final}-T_{initial})[/tex]
q = 0.0253 × 4000(75-25)
q = 101.2 (50)
q = 5060 W
Finally, the required heat of the flux is determined by using the formula:
[tex]q" = \dfrac{q}{A_s}[/tex]
[tex]q" = \dfrac{q}{\pi D L}[/tex]
[tex]q" = \dfrac{5060}{\pi \times 0.0127 \times 10}[/tex]
q" = 12682.268 W/m²
The required heat flux = 12682.268 W/m²