Question

For what values of a does the equation ax^2+x+4=0 have only one real solution?

Answer 1

Answer:

1/16

Step-by-step explanation:

To have one real solution, the discriminant must be 0.

b² − 4ac = 0

1² − 4a(4) = 0

1 − 16a = 0

a = 1/16