sme12south sme12south

26-11-2020
Mathematics

contestada

x+5y=20
x+3y=14

x=
y=

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Trujilloamy96 Trujilloamy96

26-11-2020

Answer:y = − 1 5 x + 4

Step-by-step explanation:

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meowmeow223334 meowmeow223334

26-11-2020

Do elimination
x + 5y = 20
x + 3y = 14
Subtract both equations
2y = 6
y = 3
Plug in 3 for y and solve for x
x + 5(3) = 20
x + 15 = 20
x = 5
In conclusion, x = 5, y = 3

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