Answer:
Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
[tex]m[/tex] - slope
[tex]b[/tex] - y-intercept
Given
[tex]m=-\dfrac{8}{7}[/tex]
and point [tex](7;\ -5)[/tex]
Substitute the value of the slope and the coordinates of the point ot the equation of a line:
[tex]-5=-\dfrac{8}{7\!\!\!\!\diagup}\cdot7\!\!\!\!\diagup+b[/tex] cancel 7
[tex]-5=-8+b[/tex] add 8 to both sides
[tex]-5+8=-8+8+b[/tex]
[tex]3=b\to b=3[/tex]
Therefore we have the equation of the line:
[tex]y=-\dfrac{8}{7}x+3[/tex]
Substitute (x, 3) to the equation:
[tex]3=-\dfrac{8}{7}x+3[/tex] subtract 3 from both sides
[tex]3-3=-\dfrac{8}{7}x+3-3[/tex]
[tex]0=-\dfrac{8}{7}x[/tex] divide both sides by (-8/7)
[tex]0=x\to x=0[/tex]