Question

What is the rectangular form of 12(cos(Pi) + isin(Pi))?

12
-12
12 + i
–12 + i

Answer 1

Answer:

see answer below to make it easier.

Step-by-step explanation:

Answer 2

The rectangular form of the polar expression $12(cos\pi+ isin\pi)$ is -12

The given equation is:

$12(cos\pi+ isin\pi)$

The above equation is in polar form

Note that:

$cos \pi = -1\\\\sin\pi = 0$

Substituting $cos \pi = -1$ and $sin \pi = 0$ into the expression $12(cos\pi+ isin\pi)$ in order to get the rectangular form of the expression

$12(cos\pi+ isin\pi)$

=  12(-1   +   1(0))

=  12 ( -1  +  0)

=  12(-1)

=  -12

Therefore, the rectangular form of the polar expression $12(cos\pi+ isin\pi)$ is -12

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