Answer:
The value is [tex]y = 0.0458 \ m[/tex]
Explanation:
From the question we are told that
The initial amplitude is A = 2.5 \ m
The time considered is t = 20 s
Generally the amplitude at time t is mathematically represented as
[tex]y = Ae^{- \frac{t}{\tau} }[/tex]
Here [tex]\tau[/tex] is the time constant let assume the value to be [tex]\tau = 5 \ s[/tex]
So
[tex]y = 2.5 * e^{- \frac{20}{5} }[/tex]
=> [tex]y = 0.0458 \ m[/tex]
