Question

Its velocity changes at different time intervals. Calculate the instantaneous
velocity at time 3 sec. The distance is given by equation 2t² – 4t

Answer 1

Answer:

The instantaneous velocity at time 3 sec is 8 (no units specified).

Explanation:

Instantaneous Velocity

The instantaneous velocity of an object is the derivative of the distance function with respect to time.

The distance is given by the function:

$x(t)=2t^2 - 4t$

Now we compute the instantaneous velocity function by taking the derivative of x:

$\displaystyle v(t) = \frac{dx}{dt}$

$\displaystyle v(t) = \frac{d(2t^2 - 4t)}{dt}$

$v(t) =4t -4$

Now evaluate the velocity for t=3 sec:

$v(3) =4(3) -4$

$v(3) =12 -4 = 8$

The instantaneous velocity at time 3 sec is 8 (no units specified).