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∠A and \angle B∠B are vertical angles. If m\angle A=(3x+26)^{\circ}∠A=(3x+26) ∘ and m\angle B=(x+20)^{\circ}∠B=(x+20) ∘ , then find the value of x.

Respuesta :

Answer:

The value of x is -3

Step-by-step explanation:

  • The vertical angles are equal in measures

∵ ∠A and ∠B are vertical angles

→ By using the rule above

m∠A = m∠B

∵ m∠A = (3x + 26)°

∵ m∠B = (x + 20)°

→ Equate their measures

3x + 26 = x + 20

→ Subtract x from both sides

∵ 3x - x + 26 = x - x + 20

∴ 2x + 26 = 20

→ Subtract 26 from both sides

∵ 2x + 26 - 26 = 20 - 26

∴ 2x = -6

→ Divide both sides by 2

∵ [tex]\frac{2x}{2}[/tex] = [tex]\frac{-6}{2}[/tex]

x = -3

The value of x is -3

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