Question

A study conducted by the Center for Disease Control that asked 15,000 students about
their sleep habits showed that about 73% of high school students did not get the
required 8 hours of sleep per night. Let p be the proportion of high school students who
do not get 8 hours of sleep daily.
What is the sampling distribution of p?

Answer 1

Answer:

The sampling distribution of $\hat p$ is: $\hat p\sim N(p,\ \frac{p(1-p)}{n})$.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

The study was conducted using the data from 15,000 students.

Since the sample size is so large, i.e. n = 15000 > 30, the central limit theorem is applicable to approximate the sampling distribution of sample proportions.

So, the sampling distribution of $\hat p$ is: $\hat p\sim N(p,\ \frac{p(1-p)}{n})$.