I would like to ask anyone if they would mind helping me if they could explain in a way that makes sense, how to find the y-intercept with two points... please help me, google tells me how but my head hurts and it makes no sense TwT ty in advance!!

Ok so the two points that are given need to be in the form of y2-y1 over x2-x1, meaning the x value from the second set of points needs to be subtracted from the x value from the first set of points, and it is the same for the y values. Then that gives you the slope. You add the slope to the equation y=mx+b. The slope is m, so you put the slope in the m spot. If the slope were 3, it would look like y=3x+b because it is in the m spot. Then, you can choose any 1 set of points given and plug it into the equation. I am going to use the slope 3 , like the last example, and plug it in with the set of points. Say the point was (5,2), you will plug the x value, which is 10 in the situation, next to the the slope. The slope will then be 3(5). Then you will plug in the y value, which is 2, into the y place. At the end, the equation will look like this: 2=3(5)+b. Then you multiply 3 and 5, which is 15, and subtract 2 and 15 which will give you -13. The answer will then be -13=b. That is the y-intercept.

Step-by-step explanation:

averygrace1011 averygrace1011 · Answer 2 · 2020-11-21T03:30:53+01:00

hey! if you have the equation, for example:

y=3x+4

the y-intercept would be 4! this is an easy hack to use if you already have the equation. in an equation, the number on the very end will always be your y-intercept if it is correctly written in slope intercept form.

if you do not have the equation but have the points, the y-intercept would be the point on the line that touches the y-axis first.

for example:

the line crosses through the 3rd line on the y axis. your y-intercept would be 3. it is the point in which your line crosses on the y-axis line that goes up and down the middle of the graph.

comment on my answer if you have any questions! hopefully this helps.