Question

A quadratic equation is shown below.
6x^2 = 10x - 1
What are the solutions to the quadratic equation?

Answer 1

Answer:

Two roots are:

$x = \frac{ 5 + \sqrt{19}}{6}\\x = \frac{ 5 - \sqrt{19}}{6}$

Step-by-step explanation:

$6x^2 = 10x - 1\\6x^2 - 10x + 1 = 0\\\\x = \frac{ 10 + \sqrt{10^2-4*6}}{2*6}\\x = \frac{ 10 + \sqrt{76}}{12}\\x = \frac{ 5 + \sqrt{19}}{6}\\x = \frac{ 5 - \sqrt{19}}{6}$