find an equation for the line below
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Answer:
[tex]y+1=\frac{-2}{3} (x+4)[/tex]
Step-by-step explanation:
you can use the equation point-slope of a line
(y-y1)= m(x-x1)
m is the slope =rise /run
to get from the lower point on the line to the other you rise 4 units and run -6 units so m= -4/6= -2/3
now that you have the slope pick you need one point
pick any poin on the line for example (-4, -1)
now you substitute into the point-slope equation point (-4,-1) and slope -2/3
(y+1)= -2/3(x+4)
in standard form will be
y=[tex]\frac{-2x}{3} -\frac{2*4}{3} -1[/tex]
y=[tex]\frac{-2x}{3}- \frac{5}{3}[/tex]