Question

. You are standing at the top of a high cliff. You drop a rock and it hits the ground 4
seconds later. How fast was it going when it hits the ground?

Answer 1

Answer:

V = -39.2m/s

Explanation:

Given the following data

Time, t = 4secs

Since the rock is falling, we know that the initial velocity = 0

Acceleration due to gravity = 9.8m/s²

To find the final velocity, we would use the first equation of motion

V = U + at

Substituting into the equation, we have

V = 0 + (-9.8*4)

V = -39.2m/s