Question

Write in slope intercept form of the equation of the line parallel to y= -2x + 5 and that passes through the point (3,1)

Answer 1

Answer:

y = -2x + 7

Step-by-step explanation:

In a equation thats parallel to y = -2x + 5, we have the same slope but different y intercepts (b).

SO we plug in point (3, 1) into y = mx + b

y = -2x + b

1 = -2(3) + b

1 + 6 = b

b = 7

So just plug in b back into the equation

y = mx + b

y = -2x + 7

Answer 2

Answer:

Step-by-step explanation:

y= -2x + 7

using point-slope formula:

y - y1 = m(x - x1)

Substitute:

y - 1 = m(x - 3)

Now, what is m and how do we find it?

m represents the slope. To find the slope in this circumstance, we have to look at the equation that we were given in the problem.

y= -2x + 5

Since we are trying to find a line parallel to this equation, we will be using the same slope that this uses.

The slope in the equation is -2.

Let’s substitute -2 for m.

y - 1 = -2(x - 3)

Now distribute:

y - 1 = -2x +6

Add 1 to both sides:

y = -2x + 7

Now we have an equation in slope-intercept form that is parallel to y= -2x + 5 and runs through the point (3, 1).