Answer:
0.835 Kg
Explanation:
We'll begin by calculating the number of mole of oxygen that will fill 585 L tank at STP. This can be obtained as follow:
1 mole of oxygen (O2) occupies 22.4 L at STP.
Therefore, Xmol of oxygen will occupy 585 L tank at STP i.e
Xmol of oxygen = 585/22.4
Xmol of oxygen = 26.12 moles
Next, we shall determine the mass of 26.12 moles of oxygen. This can be obtained as follow:
Mole of O2 = 26.12 moles
Molar mass of O2 = 2 × 16 = 32 g/mol
Mass of O2 =?
Mole = mass /Molar mass
26.12 = mass of O2 /32
Cross multiply
Mass of O2 = 26.12 × 32
Mass of O2 = 835.84 g
Finally, we shall convert 835.84 g to Kg. This can be obtained as follow:
1000 g = 1 Kg
Therefore,
835.84 g = 835.84 g × 1 Kg / 1000 g
835.84 g = 0.835 Kg
Thus, 835.84 g is equivalent to 0.835 Kg.
Therefore, the mass of oxygen needed to fill the 585 L tank at STP is 0.835 Kg
