Answer:
1.) y = -6
2.) y = 5/3x - 7
3.) y = 5
4.) y = -3x + 1
5.) x = -3
Step-by-step explanation:
So the equation you want to use is this: [tex]\frac{y2-y1}{x2-x1}[/tex]
1.) Plug in
[tex]\frac{-6 - (-6)}{6 - 2} \\\\\frac{0}{4} = 0\\[/tex]
This line is zero slope to find the y-intercept get one of you points and plug them and the slope into this equation y = mx+ b. We will use (2,-6)
-6 = 0(2) + b (b represents y-intercept) (0*2=0)
-6 = b
So the equation is y = -6
2.) Do the same thing.
[tex]\frac{3-8}{6-9} \\\\\frac{-5}{-3} =\frac{5}{3}[/tex]
It's positive because when you divide a negative by a negative you get a positive. Plug in a point (6, 3) y = mx + b (b represents y-intercept)
3 = 5/3(6) + b (5/3*6 = 10)
3 = 10 + b (subtract 10 on both sides)
-7 = b
y = 5/3x - 7
3.) For this one you are just going to point slope form. y - y1 = m(x - x1)
Plug in
y - 5 = 0(x - (-8))
y - 5 = 0 (add 5 to both sides)
y = 5
4.) Do [tex]\frac{y2 - y1}{x2 - x1}[/tex] for this one
Plug in
[tex]\frac{-5 - 7}{2 - (-2)} \\\\\frac{-12}{4} = -3[/tex]
So the slope is -3. Plug into y = mx + b with the point (2, -5)
-5 = -3(2) + b (b represents y-intercept)
-5 = -6 + b (add 6 to both sides)
1 = b
The equation is y = -3x + 1
5.) Do the same thing as #4
[tex]\frac{-8 - (-5)}{6 - 6} \\\\\frac{-3}{0}[/tex]
This slope is undefined
Since you can't divide by 0 the equation would be
x = -3
Hope this helps ya!!
