Given:
Seven hot dogs and two hamburgers cost 14.50
Two hot dogs and seven hamburgers cost 17.00.
To find:
The cost of one hot dog and the cost of one hamburger.
Solution:
Let the cost of one hot dog be x and the cost of one hamburger be y.
According to the question,
[tex]7x+2y=14.50[/tex] ...(i)
[tex]2x+7y=17.00[/tex] ...(ii)
Multiply (i) by 7.
[tex]49x+14y=101.5[/tex] ...(iii)
Multiply (ii) by 2.
[tex]4x+14y=34.00[/tex] ...(iv)
Subtract (iv) from (iii).
[tex]49x-4x=101.5-34[/tex]
[tex]45x=67.5[/tex]
Divide both sides by 45.
[tex]x=1.5[/tex]
Put x=1.5 in (i).
[tex]7(1.5)+2y=14.50[/tex]
[tex]10.50+2y=14.50[/tex]
[tex]2y=14.50-10.50[/tex]
[tex]2y=4[/tex]
Divide both sides by 2.
[tex]y=2[/tex]
Therefore, the cost of one hot dog is 1.5 and the cost of one hamburger is 2.
Answer:
the other person is correct
Step-by-step explanation:
i put in the answers and it’s correct
