Question

The tens digit of a two digit number is five more than the units digit. Seven times the sum of the digits of this number is 3 less than the number itself. Find the number.

Answer 1

Answer:

94

Step-by-step explanation:

Let the unit's digit = $y$

Let the ten's digit = $x$

Then the number will be equal to $10x+y$

Now, using the given statement:

$x=y+5 ..... (1)$

$7(x+y) = 10x+y-3\\\Rightarrow 7x+7y=10x+y-3\\\Rightarrow 6y-3x=-3 ..... (2)$

Now, using the equation (1) in equation (2):

$6y-3(y+5) =-3\\\Rightarrow 3y-12=0\\\Rightarrow y =4$

By equation (1):

$x = 4+5 \\\Rightarrow x =9$

Therefore, the number is :

$10x+y= 10\times 9 +4 = \bold{94}$