Question

Consider random samples of size 50 from a population with proportion 0.35.
Find the mean and standard error of the distribution of sample proportions.
Round your answer for the mean to two decimal places, and your answer for the standard error to three decimal places.

Answer 1

Answer:

The mean is  $\mu_{\^ p } = p = 0.35$    

The standard error  is  $SE = 0.06745$

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  50  

    The population proportion is $p = 0.35$

Generally given that the sample size is large enough , then the mean of the distribution is  mathematically represented as

          $\mu_{\^ p } = p = 0.35$    

Generally the standard error of the distribution is mathematically represented as

        $SE = \sqrt{\frac{p (1- p )}{n} }$

=>     $SE = \sqrt{\frac{0.35 (1- 0.35 )}{50} }$

=>     $SE = 0.06745$