Write the net ionic equation for the reaction of aqueous copper(II) chloride with aqueous sodium phosphate. Remember to include the states of matter.

Respuesta :

Answer:

3 Cu²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Cu₃(PO₄)₂(s)

Explanation:

Let's consider the molecular equation between aqueous copper(II) chloride and aqueous sodium phosphate.

3 CuCl₂(aq) + 2 Na₃PO₄(aq) ⇒ 6 NaCl(aq) + Cu₃(PO₄)₂(s)

The complete ionic equation includes all the ions and insoluble species.

3 Cu²⁺(aq) + 6 Cl⁻(aq) + 6 Na⁺(aq) + 2 PO₄³⁻(aq) ⇒ 6 Na⁺(aq) + 6 Cl⁻(aq) + Cu₃(PO₄)₂(s)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and insoluble species.

3 Cu²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Cu₃(PO₄)₂(s)

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