Answer:
A) T = 24
b) 77.953
c) t > 63.78 , t < 5.6
d) (7.029,27.5) and (40.97,55.23)
Step-by-step explanation:
Given
F(t) = t^2 e^-t/12, t ≥ 0
a) time for maximum concentration
t = 24
b) determine maximum concentration at maximum time
F(24) = 77.953
c) determine when the concentration will dip below the level of 20.0
when t > 63.78 , t < 5.6
d) concentration function changes concavity ( estimated from a graph )
(7.029,27.5) and (40.97,55.23)
attached below is the detailed solution