Question

Methane (CH4) is the main component of marsh gas. Heating methane in the presence of sulfur produces carbon disulfide and hydrogen sulfide as the only products. (a) Write the balanced chemical equation for the reaction of methane and sulfur. (Use the lowest possible coefficients. Include states of matter under SATP conditions in your answer.)(b) Calculate the theoretical yield of carbon disulfide when g of methane is reacted with an equal mass of sulfur.

Answer 1

Answer:

71.25 g

Explanation:

Methane + Sulfur = Carbon Disulfide + Hydrogen Sulfide

The equation is given as;

CH4 + S --> CS2 + H2S

Upon balancing, we have;

CH4(g) + 4S(s) → CS2(l) + 2H2S(g)

Theoretical yield of carbon disulphide;

Equal masses of 120g

The limiting reactant is sulphur It determines how much of the product is formed.

From the equation;

4 mol of S produces 1 mol of CS2

upon converting to masses using; Mass = number of mol * Molar mass

4 mol of S = 4 * 32

1 mol of CS2 = 76g

128g of S produces 76g of C2, 120g would produce ?

128 = 76

120 = x

x = 120 * 76 / 128

x = 71.25g

Answer 2

(a).  The balanced chemical reaction will be:

$\rm CH_4\;(g)+\;4\;S\;(s)\rightarrow\;CS_2\;(l)+\;2\;H_2S\;(g)$

(b). 120 grams of sulfur will produce 71.25 grams of carbon disulfide.

The heating of methane in the presence of sulfur can be given by:

$\rm CH_4\;+\;S\;\rightarrow\;CS_2\;+\;H_2S$

(a). The lowest possible coefficients have been used to balance the number of elements on both sides i.e. reactant and the product.

$\rm CH_4\;+\;4\;S\;\rightarrow\;CS_2\;+\;2\;H_2S$

The state of the elements has also been mentioned in the chemical equation. The state of methane is gas, sulfur is solid, carbon disulfide is liquid and hydrogen disulfide is gas.

Thus the balanced chemical reaction will be:

$\rm CH_4\;(g)+\;4\;S\;(s)\rightarrow\;CS_2\;(l)+\;2\;H_2S\;(g)$

(b). When 120 grams of sulfur reacts, the yield of carbon disulfide will be:

From the balanced equation, 4 moles of sulfur will give 1 mole of carbon disulfide.

4 moles of Sulfur = mole $\times$ molecular weight

4 moles of Sulfur = 4 $\times$ 32

4 moles of Sulfur = 128 grams.

1 mole of carbon disulfide = 76 grams.

So, 128 grams of sulfur produces, 76 grams of carbon disulfide.

Thus, 120 grams of sulfur will produce = $\rm \dfrac{76}{128}\;\times\;120$ grams Carbon disulfide

120 grams of sulfur will produce = 71.25 grams of Carbon disulfide.

Thus, 120 grams of sulfur will produce 71.25 grams of carbon disulfide.

For more information about a chemical reaction, refer to the link:

https://brainly.com/question/1689737