Question

A toaster is rated at 600W, when connected to a120-V source. What current does the toaster carry, and what is its resistance?

Answer 1

Explanation:

Given parameters:

Power of the toaster  = 600W

Voltage  = 120V

Unknown:

Current = ?

Resistance = ?

Solution:

The power in the circuit is related to resistance and current using the expression below;

       P = IV  

       P = $\frac{V^{2} }{R}$

P is the power

I is the current

V is the voltage

R is the resistance

    To find the current;

        I = $\frac{P}{V}$   = $\frac{600}{120}$  = 5A

     Now, resistance;

       V²   = PR

       R = $\frac{V^{2} }{P}$   = $\frac{120^{2} }{600}$  = 24ohms

Answer 2

Current, I=5A

Resistance, R=24 ohms

Firstly, let's write the given values:

Power, P=600W

Voltage, V=120V

To find:

Current, I=?

Resistance, R=?

Lets understand ohm's Law:

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.

Formula for Ohm's law:

$V=I.R$

The relation between power, current and resistance can be represented as:$P=I.V$

Or

$P=\frac{V^2}{R}$

To find current:

$I=\frac{P}{V}$

So on substituting given values,

$I=\frac{600}{120} =5A$

To find resistance:

$R=\frac{V^2}{P}$

So on substituting given values,

$R=\frac{14400}{600} =24 \text{ohms}$

Learn more:

brainly.com/question/16014555