Question

How many Mg atoms are found in 1.00 mole of MgO?

Answer 1

Answer:

From the equation above we get 1 amu = 1g/NA or 1 amu = 1.66054x10^-24 g. Thus, a mole of magnesium atoms has a mass of NA x 24.305 amu x (1.66054x10^-24 g/amu) = 24.305 g. A mole of magnesium atoms has a mass of 24.305 g.

Explanation:

Answer 2

1 mole of MgO has 146.35 × $\rm 10^2^3$ atoms of Mg.

The number of atoms found in a mole of compound has been given by relationship between the mole and the Avogadro number. The Avogadro number has been the constant that has been given by the number 6.023 × $\rm 10^2^3$.

The relationship between the atoms and mole has been given by:

1 mole = 6.023 × $\rm 10^2^3$ atoms.

So, the number of atoms that has been present in1 mole of the MgO has been equivalent to the Avogadro number.

Thus, 1 mole of MgO has 6.023 × $\rm 10^2^3$ atoms.

The mass of there has been 1 molecule of Mg in the MgO compound, thus, the atoms of Mg can be given by:

Mg atoms = Mass of Mg × Avogadro number

Mg atoms = 24.3g × 6.023 × $\rm 10^2^3$

Mg atoms = 146.35 × $\rm 10^2^3$

Thus, 1 mole of MgO has 146.35 × $\rm 10^2^3$ atoms of Mg.

For more information about the number of atoms, refer to to the link:

https://brainly.com/question/4206478