Question

Given NL bisects KNM and KLM. Prove NKL equals NML

Answer 1

Answer:

1.  NL bisects <KNM and <KLM = Given

2. <KNL = <MNL = def. of angle bisector

3. <KLN = <MLN = def. of angle bisector

4. NL = NL = Reflexive Property

5. (triangle) NKL = (triangle) NML = ASA

Step-by-step explanation:

Answer 2

ΔNKL ≅ ΔNML by Angle Sie Angle (ASA) congruence

hence (c) option is correct

Given that

NL bisects ∠KNM and ∠KLM

To Prove

ΔNKL ≅ ΔNML

∠KNM =  ∠KLM  (given)

According to ASA ( Angle Side Angle ) rule of congruence if two angles and the included side of one triangle is equal to the corresponding two angles and the included side of another triangle than we say that the two triangles are congruent by ASA rule of congruence.

Here

NL bisects ∠KNM and ∠KLM

hence by definition of angle bisector we can say that

∠KNL = ∠LNM

∠KLN = ∠MLN

NL = NL  (Common included side )

So we can say  that

ΔNKL ≅ ΔNML (By ASA congruence) hence

from given figure  (c) option is correct.

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https://brainly.com/question/20903156