MNO and MPO are isosceles triangles. Find angle t
![MNO and MPO are isosceles triangles Find angle t class=](https://us-static.z-dn.net/files/dc2/619cd062d6ceb2c143519674d9783d30.jpg)
Answer:
t = 20°
Step-by-step explanation:
Recall that the base angles of an isosceles ∆ are equal to each other.
This means that:
<NMO and <NOM of ∆MNO are congruent to each other.
Thus,
m<NMO = ½(180 - m<N) = ½(180 - 70)
m<NMO = ½(110)
m<NMO = 55°
Also, <PMO and <POM are congruent to each other. Thus:
m<PMO = ½(180 - m<P) = ½(180 - 110)
m<PMO = ½(70)
m<PMO = 35°
Therefore,
m<NMO = t + m<PMO (angle addition postulate)
55° = t + 35° (substitution)
Subtract 35 from each side
55° - 35° = t
20° = t
t = 20°