Question

8. A tank shoots a projectile at an angle of 67* above the horizon and at a speed of 53 m/s
toward an enemy tank. How far away will the enemy be located for a direct hit?
I

Answer 1

Answer:

Explanation:

We are tp calculate the range of the projectile. This is expressed as;

R = 2Usin theta/g

Given

U = 53m/s

Theta = 67°

Substitute;

R = 2(53)sin67/9.8

R = 106sin67/9.8

R = 106(0.9205)/9.8

R = 97.57/9.8

R = 9.96m

Hence the enemy is 9.98m located for a direct hit.