Question

A ball with an initial velocity of 2 m/s rolls for a period of 3 seconds. If the ball is uniformly accelerating at a rate of 3 m/s2, what will be the ball’s final velocity?

Answer 1

Answer: 11 m/s

vinitial=2 m/s

time=3 s

acceleration = 3 m/s^2

vfinal = ?

The key here is that it is a constant acceleration, so we can use the constant acceleration equations. The easiest one to use would be:

vfinal=vinitial + a*t

We need vfinal, so algebraically we are ready to put in numbers into the equation:

vfinal=vinitial + a*t = 2 m/s + (3 m/s^2)*(3 s ) = 11 m/s is the final velocity

Answer 2

The ball's final velocity is 11 m/s

From one of equations of kinematics for linear motion

We have that

v = u + at

Where v is the final velocity

u is the initial velocity

a is the acceleration

and t is the time

From the given information in the question

u = 2 m/s

t = 3 secs

a = 3 m/s²

Putting these parameters into the above formula

v = u + at

We get

v = 2 + (3×3)

v = 2 + 9

v = 11 m/s

Hence, the ball's final velocity is 11 m/s

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