Question

An artificial satellite orbits Earth at a speed of 7800 m/s and a height of 200 km above Earth's surface. The satellite experiences
an acceleration due to gravity of
A
39 m/s2
B
less than 39 m/s2 but greater than 9.8 m/s2
с
9.8 m/s2
D
less than 9.8 m/s2 but greater than zero
E
zero

Answer 1

Answer: less than 9.8 m/s^2 but greater than zero

Explanation:

This answer is correct the other isnt

Answer 2

The acceleration due to gravity experienced by this artificial satellite is: D. less than 9.8 m/s2 but greater than zero.

Given the following data:

• Velocity = 7800 m/s

• Height = 200 km

Conversion:

Height = 200 km to meters = 200,000 meters.

To determine the acceleration due to gravity experienced by the satellite:

Mathematically, the speed of an object in orbit is given by the formula:

$V = \sqrt{2gh}$

Where:

• g is the acceleration due to gravity.

• h is the height.

• V is the speed.

Making g the subject of formula, we have:

$g = \frac{V^2}{2h}$

Ideally, we know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 $m/s^2$.

Generally, the value of acceleration due to gravity (g) falls or decreases as height (h) increases.

Therefore, the acceleration due to gravity experienced by this artificial satellite would be less than 9.8  $m/s^2$ but greater than zero.

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