Answer:
Option (B) is correct.
Explanation:
Given that the molecules of hydrogen gas ([tex]H_2[/tex]) react with molecules of oxygen gas ([tex]O_2[/tex]) in a sealed reaction chamber to produce water ([tex]H_2O[/tex]).
The governing equation for the reaction is
[tex]2H_2 +O_2 \rightarrow 2H_2O[/tex]
From the given, the only fact that can be observed that 2 moles of [tex]H_2[/tex] and 1 mole of [tex]O_2[/tex] reacts to produce 2 moles of [tex]H_2O[/tex].
As the mass of 1 mole of [tex]H_2 = 2[/tex] grams ... (i)
The mass of 1 mole of [tex]O_2 = 32[/tex] grams ...(ii)
The mass of 1 mole of [tex]H_2O = 18[/tex] grams (iii)
Now, the mass of the reactant = Mass of 2 moles of [tex]H_2[/tex] + mass 1 mole of [tex]O_2[/tex]
[tex]= 2 \times 2 + 32[/tex] [ using equations (i) and (ii)]
[tex]=4+32 = 36[/tex] grams.
Mass of the product = Mass of 2 moles of [tex]H_2O[/tex]
[tex]=2\times 18[/tex] [ using equations (iii)]
=36 grams
As the mass of reactants = mass of the product.
So, mass is conserved.
Hence, option (B) is correct.