Question

A sled is pulled at a constant velocity across a horizontal snow surface. If a force of 8.0 times 10^1 N is being applied to the sled rope at an angle of 53 degrees to the grind, what is the force of friction between the sled and the snow?

Answer 1

Answer:

48 Newtons

Explanation:

• There is no acceleration and net forces.
• $8*10x^{-1} N cos(53) = friction$
• Answer: 48.15 Newtons

Answer 2

The force of friction between the sled and the snow is 48 newtons.

Given that,

• The force is $8.0 \times 10^{1}$.
• N is being applied to the sled rope at an angle of 53 degrees to the grind.

Based on the above information, the calculation is as follows:

$= 8\times 10x^{-1}N cos(53)$

= 48 newtons

Therefore we can conclude that the force of friction between the sled and the snow is 48 newtons.

Learn more: brainly.com/question/17127206