Question

A triangle has a perimeter of (12a^2 + 5a + 9b + 16) and side lengths (4a^2 + 9a - 8) and (2a + 2b + 10). What is the length of the third side?

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Answer 1

Answer:

8x^2-6a+9b+14

Step-by-step explanation:

P=(12a^2 + 5a + 9b + 16)

(4a^2 + 9a - 8)+ (2a + 2b + 10) +(x)= (12a^2 + 5a + 9b + 16)

(4a^2+11a+2)+(x)=(12a^2 + 5a + 9b + 16)

subtract (4a^2+11a+2) from both sides

x= 8x^2-6a+9b+14

Answer 2

Answer:

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Step-by-step explanation: