Question

A bag of marbles contains only the colors blue, yellow, and green.

If the probability of getting a yellow marble is 1/3, and the probability of getting a blue marble is 1/5, what is the probability of getting a green marble?

Answer 1

Answer:

$\frac{7}{15}$

Step-by-step explanation:

Given parameters:

Marbles in the bag  = blue, yellow, and green

Pr(yellow) = $\frac{1}{3}$  

Pr(blue) = $\frac{1}{5}$

Unknown:

Pr(green) = ?

Solution:

Probability is the likelihood of an event to occur;

 For this problem;

     Pr(yellow) + Pr(blue) + Pr(green) = 1

          $\frac{1}{3}$   +  $\frac{1}{5}$  + Pr(green)  = 1

       Pr(green)  = 1 - (   $\frac{1}{3}$   +  $\frac{1}{5}$  )

       Pr(green) = 1 - $\frac{8}{15}$  

       Pr(green) = $\frac{7}{15}$