As you said, we can solve this system for y by using substitution.
[tex]x = 2y - 6\\y = 3x - 7\\\\y = 3(2y - 6) - 7\\\\y = 6y - 18 - 7\\\\y = 6y - 25\\\\-5y = -25\\\\y = 5[/tex]
Now, using what we got for y, we plug it into one of the original equations to solve for x.
[tex]x = 2(5) - 6\\\\x = 10 - 6\\\\x = 4[/tex]
Now we have the solution of this system.
[tex](4, 5)[/tex]