Question

The population of fish in a take was approximately 5.4 * 10 ^ 4 in 2012. The next year, 2013population tripled What was the opproximate population of fish in this in 2013?

Pleaseeee

Answer 1

5,4* 10^4 = 54000in 2012.
2013 = 54000*3 = 5,4*3* 10^4 = 162000 fishes. 1,62 *10^ 5

Answer 2

The population of fish in a lake was approximately 5.4 * 10 ^ 4 in 2012.

The approximate population of fish in this in 2013 since the amount of the fish tripled is 1.62 × 10⁵

Scientific notation is the proper format of denoting and representing large numbers into simpler forms multiplied by raising them to the power of 10.

Given that:

• The approximate number of fish in 2012 is: 5.4 × 10⁴

In 2013, when the population of the fish tripled the amount it was in 2012;

Then, we can calculate the total population of fish in 2013 as:

$\mathbf{=( 5.4 \times 10^4) \times 3}$

= 162000

= 1.62 × 10⁵

Therefore, we can conclude that the approximate population of fish in 2013 is: 1.62 × 10⁵

Learn more about scientific notation:

https://brainly.com/question/1705769?referrer=searchResults